3(2n-1)=(4n^2+2n+1)

Solution for 3(2n-1)=(4n^2+2n+1) equation:

3(2n-1)=(4n^2+2n+1)

We move all terms to the left:

3(2n-1)-((4n^2+2n+1))=0

We multiply parentheses

6n-((4n^2+2n+1))-3=0


We calculate terms in parentheses: -((4n^2+2n+1)), so:

(4n^2+2n+1)

We get rid of parentheses

4n^2+2n+1

Back to the equation:

-(4n^2+2n+1)


We get rid of parentheses

-4n^2+6n-2n-1-3=0

We add all the numbers together, and all the variables

-4n^2+4n-4=0

a = -4; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-4)·(-4)
Δ = -48
Delta is less than zero, so there is no solution for the equation